Let \(A\) be the matrix with columns the above vectors: \[\begin{bmatrix} 0 & -5 \\ -2 & -3 \\ -6 & -34 \\ -4 & -26 \end{bmatrix}\] Reduced row echelon form (RREF) of \(A^T\): \[\begin{bmatrix} 1 & 0 & 5 & 4 \\ 0 & 1 & 3 & 2 \end{bmatrix}\] Basis for \(W^\perp = (\textrm{Col}A)^\perp = \textrm{Nul} A^T\): \[\begin{bmatrix} -5 \\ -3 \\ 1 \\ 0 \end{bmatrix}, \qquad \begin{bmatrix} -4 \\ -2 \\ 0 \\ 1 \end{bmatrix}.\]

Problem:

Let \(W\) be the subspace spanned by the vectors    
\[
\begin{bmatrix} 
 0  \\ 
 -2  \\ 
 -6  \\ 
 -4
\end{bmatrix}, \qquad 
\begin{bmatrix} 
 -5  \\ 
 -3  \\ 
 -34  \\ 
 -26
\end{bmatrix}.\]
Find a basis for the orthogonal complement \(W^\perp\) of \(W\).

\begin{solution}
Solution:

Let \(A\) be the matrix with columns the above vectors:
\[\begin{bmatrix} 
0 & -5   \\ 
-2 & -3   \\ 
-6 & -34   \\ 
-4 & -26
\end{bmatrix}\]
Reduced row echelon form (RREF) of \(A^T\):
\[\begin{bmatrix} 
1 & 0 & 5 & 4   \\ 
0 & 1 & 3 & 2
\end{bmatrix}\]
Basis for \(W^\perp = (\textrm{Col}A)^\perp = \textrm{Nul} A^T\):   
\[\begin{bmatrix} 
 -5  \\ 
 -3  \\ 
 1  \\ 
 0
\end{bmatrix}, \qquad 
\begin{bmatrix} 
 -4  \\ 
 -2  \\ 
 0  \\ 
 1
\end{bmatrix}.\]
\end{solution}